1.

A container has 3.2 g of a certain gas at NTP. What would be the mass of the same gas contained in the same vessel at 200^(@)C and 16 atm pressure.

Answer»


Solution :Mol. WT. `(M) = (3.2)/(V) xx 22.4`, V = vol. in li. Apply `pV = (w)/(M)RT` ,
w = wt. of the GAS in 473 K and 16 atm.


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