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A container having base area A_(0). Contains mercury upto a height l_(0). At its bottom a thin tube of length 4l_(0) and cross-section area A(AltltA_(0)) having lower end closed is attached . Initially the length of mercury in tubeis 3l_(0). in reamining part 2 mole of a gas at temperature T is closed as shown in figure . Determine the work done (in joule) by gas if all mercury is displaced from tube by heating slowly the gas in the rear end of the tube by means of a heater. (Given : density of mercury = rho, atmospheric pressure P_(0) = 2l_(0)rhog, C_(v) of gas = 3//2 R, A = (3//rho)m^(2), l_(0) = (1//9)m , all units is S.I.)

Answer»

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Solution :If X is length of mercury in tube then pressure of GAS
`P' =P_(0) +rhogl_(0) + rhogx = 3rhogl_(0) + rhogx IMPLIES W= - int_(3//0)^(0) (3rhogl_(0) + rhogx) Adx = 13.5 rhogAl_(0)^(2) = 5`


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