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A container of `2` litre contain `4` moles of `N_(2)O_(5)`. On heating to `100^(@)C, N_(2)O_(5)` undergoes complete dissociation to `NO_(2)` and `O_(2)`. If rate constant for decomposition of `N_(2)O_(5)` is `6.2xx10^(-4) sec^(-1)`, select the correct statements:A. (a) The mole ratio before and after dissociation is `4:2`B. (b) The time required to complete `40%` of reaction is `824 sec`C. (c ) `t_(1//2)` of `N_(2)O_(5)` is `1117.7` sec and it is independent of temperatureD. (d) If volume of container is doubled, the rate of decomposition becomes half of the initial rate |
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Answer» Correct Answer - b, c, d `{:(,N_(2)O_(5),rarr,2NO_(2),+,1/2O_(2)),("Initial mole",4,,0,,0),("After diss. mole",0,,8,,2):}` `:.` Mole ratio`=4/10=2:5` `t_(1//2)=0.693/K=0.693/(6.2xx10^(-4))=1117.7 sec` But it depends upon temp. as `K` depends upon `T`. `t_(40%)=2.303/(6.2xx10^(-4))"log"100/((100-40))` `=824 sec` Rate `r_(1)=K [N_(2)O_(5)]`, If `V` is double the concentration becomes half. `:. r_(2)=Kxx1/2[N_(2)O_(5)]` `:. r_(1)/r_(2)=2/1` |
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