InterviewSolution
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InterviewSolution
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A container of volume 50cc contains air (mean molecular weight =28.8g) and is open to atmosphere where the pressure is 100kPa. The container is kept in a bath containing melting ice`(0^(@)C.(a) Find the mass of the air in the container when thermal equlibrium is reached.(b) the container is mow placed in another bath containing boling water`(100^(@)C)`. Find the mass of air in the container. (C) The container is mow closed and placed in the melting-ice bath. Find the pressure of the air when thermal equilibrium is reached . |
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Answer» Given, `(V= 50 cc. = (50 xx (10^-6)(m^3)))` ` P= 100KPa = (10^5)Pa,` ` M = 28.8 g ` ` (a) PV = n(RT_1) ` ` rArr PV = (m/M)(RT_1)` ` rArr m = (PMV/ RT_1)` ` = ((10^5) xx 28.8 xx 50 xx (10^-6)/ 8.3 xx 273)` ` = 50 xx 28.8 xx (10^1)/ 8.3 xx373)` ` 0.0465 gm ` (c) When the vessel is closed ` P xx 50 xx (10^-6) = (0.0465/ 28.8) xx 8.3 xx 273` rArr P=(0.0465 xx 8.3 xx 273 / 28.8 xx 50 xx (10^-6))` ` = 0.07316 xx (10 ^6)Pa` ` = 73.16 KPa` ` = 73 KPa ` |
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