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A convergent lens with a focal length of f=10cm is cut into two halves that are then moved apart to a distance of d=0.5 mm (a double lens). Find the fringe width on screen at a distance of 60 cm behind the lens if a point sources of monochromatic light (lambda=5000Å) is placed in front of the lens at a distance of a = 15cm from it. |
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Answer» `1/v + 1/15 = 1/10` `:. V = 30 cm` `m = v/u = 30/(-15) = -2`  Distance between two SLITS, d = 1.5 MM, D =30 cm Fringe width, `omega = (lambdaD)/(d)` `=((5.0xx10^(-7))(0.3))/((1.5xx10^(-3))) =10^(-4) m` =0.1 mm |
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