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A convex lens has a focal length f. It is cut inti two parts along the dotted lines as shown ii figure. The focal length of each part will be…....... . |
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Answer» `f/2` `1/f=(n-1)(1/R_1-1/R_2)(R_1=R,R_2=-R)` `=(n-1)(1/R+1/R)=(n-1)(2/R)` `thereforef=(R)/(2(n-1))` …......(1) Now a convex lens is cut into two PARTS along perpendicular direction to the axis, the plano convex lens will prepared. The FOCALLENGTH of this lens is `f_1` then, `(1)/(f_1)=(n-1)(1/R_1-1/R_2)` `[R_1=prop(infinite),R_2=-R]` `therefore1/f_1=(n-1)1/R` `therefore f_1=(R)/(n-1)=2f` 
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