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A convex lens is in contact with a concave lens. The magnitude of the ratio of their focal lengths is (2)/(3). Their equivalent focal length is 30 cm. What are their individual focal lengths? |
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Answer» `-75CM, 50cm` As `(1)/(f)=(1)/(f)+(1)/(f_(2))`, hence `(1)/(30)=(1)/(f_(1))+(1)/((-(3)/(2)f_(1)))=(1)/(f_(1))-(2)/(3f_(1))=(1)/(3f_(1))RARR f_(1)=10 cm and f_(2)=-15cm`. |
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