1.

A convex lens is placed between an object and a screen which are a fixed distance apart. For one position of the lens the magnification of the image obtained on the screen is m_1. When the lens is I moved by a distance d, the magnification of the image obtained on the same screen is m_2. The focal length of the lens is (m_1 gt m_2)

Answer»

`(d)/((m_1 - mu_2))`
`(d)/((m_1 + m_2))`
`d m_1/m_2`
`d m_2/m_1`

ANSWER :A


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