A copper block of mass `2.5 kg` is heated in a furnace to a temperature of `500^(@)C` and then placed on a large ice block. What is the maximum amount (approx.) of ice that can melt? (Specific heat copper `= 0.39 J//g^(@)C` heat of fusion of water `= 335 J//g`).

A copper block of mass `2.5 kg` is heated in a furnace to a temperatur

1.	A copper block of mass `2.5 kg` is heated in a furnace to a temperature of `500^(@)C` and then placed on a large ice block. What is the maximum amount (approx.) of ice that can melt? (Specific heat copper `= 0.39 J//g^(@)C` heat of fusion of water `= 335 J//g`).
Answer» Mass of the copper block, m = 2.5 kg = 2500 g Rise in the temperature of the copper block, `Delta theta = 500^(@)C` Specific heat of copper, `C = 0.39 J g^(–1)"@C^(–1)` Heat of fusion of water, `L = 335 J g^(–1)` The maximum heat the copper block can lose, Q = mCΔθ = 2500 × 0.39 × 500 = 2500 × 0.39 × 500 Let `m^(1) g` be the amount of ice that melts when the copper block is placed on the ice block. The heat gained by the melted ice, `Q = m^(1)L` `:.m_(1)=(Q)/(L)=(487500)/(335)=1455.22 g` Hence, the maximum amount of ice that can melt is 1.45 kg

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A copper block of mass `2.5 kg` is heated in a furnace to a temperature of `500^(@)C` and then placed on a large ice block. What is the maximum amount (approx.) of ice that can melt? (Specific heat copper `= 0.39 J//g^(@)C` heat of fusion of water `= 335 J//g`).

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