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A copper coin has a mass of 63.0g. Calculate the nuclear energy that would be required to separate all the neutrons and protons form each other. The coin is entirely made of ""_(29)^(63)Cu atoms. Mass of ""_(29)^(63)Cu atom = 62.92960u mass of proton = 1.00727u Mass of neutron = 1.00866u Avogadro's number = 6.022 xx 10^(23) |
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Answer» Solution :`N= (6.023 XX 10^(23))/(63) xx 63 = 6.023 xx 10^(23)` atoms Mass defect, `Delta m= Zm_(p) + (A-Z)m_(n)-M` `=29 xx 1.00727 + 34 xx 1.00866-62.92960` `Delta m= 0.5759` amu Binding energy `= Delta m xx 931 MeV` `=0.5759 xx 931= 536.1629 MeV` TOTAL energy REQUIRED to separate the NUCLEONS from each other `E xx N= 536.1629 xx 6.023 xx 10^(23)` `=3229.309 xx 10^(23)MeV` |
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