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A copper collar is to fit tightly about a steel shaft that has a diameter of 6 cm at `20^@C`. The inside diameter of the copper collar at the temperature is `5.98cm` If the breaking stress of copper is `230 N//m^2`, at what temperature will the copper collar break as it cools?A. `20^@C`B. `47^@C`C. `94^@C`D. `217^@C` |
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Answer» Correct Answer - C `alphaLDeltaT+L((F)/(A))/(alphaY)=0` `DeltaT=((F)/(A))/(alphaY)=(230xx10^6(N)/(m^2))/((17xx10^-6K^-1)(110xx10^9(N)/(m^2))` `=-123K=-123^@C` Final temperature at which the copper collar breaks `T_f=T_i+DeltaT=217^@C-123^@C=94^@C` |
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