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A copper collar is to fit tightly about a steel shaft that has a diameter of 6 cm at `20^@C`. The inside diameter of the copper collar at the temperature is `5.98cm` Q. To what temperature must the copper collar be raised to that it will just slip on the steel shaft, assuming the steel shaft remains at `20^@C` ? `(alpha_("copper")=17xx10^(-6)//K`)A. `324^@C`B. `21.7^@C`C. `217^@C`D. `32.4^@C` |
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Answer» Correct Answer - C `l_1=l_0(1+alphat)` `(2pixx6)/(2)=l_0(1+alphat)` `(2pixx5.98)/(2)=l_0(1+20alpha)` `(6)/(5.98)=(1+alphat)/(1+20alpha)=((1+17xx10^-6t))/(1+20xx17xx10^-6)` `t=216.8^@Capprox217^@C` |
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