A copper connector of massm, starting from rest, slides down two conducting bars set at angle alpha to the horizontal, due to gravity (see figure). At the top the bars are interconnected trhough a resistance R. The separation between the bars is equal to l. The system is located in uniform magnetic field of induction B, perpendicular to the plane in which the connectr slides. The resistance of the bars the connector and the sliding contacts, as well as the self inductance of the loop, are assumed to be negligible. The coefficient of friction between the connector and the bars is equal to (1)/(2) and alpha (a) Find the steady-state velocity of the connector. (b) How will your answer differ if the magnetic field was in opposite direction.

A copper connector of massm, starting from rest, slides down two condu

1.	A copper connector of massm, starting from rest, slides down two conducting bars set at angle alpha to the horizontal, due to gravity (see figure). At the top the bars are interconnected trhough a resistance R. The separation between the bars is equal to l. The system is located in uniform magnetic field of induction B, perpendicular to the plane in which the connectr slides. The resistance of the bars the connector and the sliding contacts, as well as the self inductance of the loop, are assumed to be negligible. The coefficient of friction between the connector and the bars is equal to (1)/(2) and alpha (a) Find the steady-state velocity of the connector. (b) How will your answer differ if the magnetic field was in opposite direction.
Answer» Answer :(a) `v = (MGR SIN alpha)/(2B^(2)L^(2))` (b) No difference

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