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A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions per second, in a uniform magnetic field of 0.1 tesla with its plane perpendicular to the field. The e.m.f. induced across the radius of the disc is |
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Answer» `pi xx 10^(-1)` volt `e=(B omega R^(2))/(2)=(0.1 xx(2pi xx 10)xx(0.1)^(2))/(2)` `rArr e=0.1 xx(0.1)^(2)xx pi xx10=pi xx 10^(-2)V` |
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