Saved Bookmarks
| 1. |
A copper electrode is dipped in 0.1 M copper sulphate solution at 25^(@)C. Calculate the electrode potential of copper. ["Given :" E_(Cu^(2+)|Cu)^(@)=0.34] |
|
Answer» SOLUTION :GIVEN that `[CU^(2+)]=0.1M` `E_(Cu^(2+)|Cu)^(@)=0.34` `E_("cell")=?` Cell reaction is `Cu_((AQ))^(2+)+2e^(-) rarr Cu_((s))` `E_("cell")=E^(@)-0.0591/nlog""([Cu])/([Cu^(2+)])` `""=0.34""0.0591/2log""1/0.1` `""=0.34-0.0296` `=0.31V`. |
|