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A copper rod length 1 am and area of cross - section 0.1" m"^(2) has its end maintained at 100^(@)C by means of 0.4 KW electric heater. What is temperature of other end in steady state ? (K=400W//mK) : |
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Answer» `90^(@)C` i.e `(Q)/(t)=0.4xx10^(3)` If T be the TEMPERATURE of other end of ROD then `("k A"(100-T))/(d)=0.4xx10^(3)` `(400xx0.1xx(100-T))/(1)=0.4xx10^(3)` `rArrT=90^(@)C` Hence correct CHOICE is (a). |
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