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A copper rod of length 2m is rotated with a speed of 10 rps in a uniform magnetic field of 1 tesla about a pivot at one end. The magnetic field is perpendicular to the plane of rotation. Find the emf induced across its ends. |
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Answer» SOLUTION :`e= (1)/(2) B omega 1^(2) = (1)/(2) B (2PI n) 1^(2)= pi B nl^(2)` `e= 3.14 xx 1 xx 10 xx 2 xx 2 = 125.6` volt |
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