InterviewSolution
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InterviewSolution
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A copper wire is dipped in AgNO_(3) solution kept in beaker A and a silver wire is dipped in a solution of copper suphate kept in beaker B. if standard electrode potential for Cu^(2+)+2e^(-)toCu is +0.34 V and for Ag^(+)+e^(-)toAg is +0.80V, predit in which beeaker the ions present willget reduced? |
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Answer» Solution :The PROBABLE reaction in BEAKER A will be `Cu+2AgNO_(3)toCu(NO_(3))_(2)+2Ag, i.E., Cu+2Ag^(+)toCu^(2+)+2Ag` `E_(CELL)` for this reaction `=-0.34+0.80=+0.46V` i.e., it is +ve. Hence, `AG^(+)` ions are reduced to Ag. |
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