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A copper wire of 10 ^(-6) m ^(2) area of cross section, carries a current of 2A. If the number of electrons per cubic meter is 8 xx 10 ^(28), calculate the current density and average drift velocity. Given, e1. 6 xx 10 ^(-19) C) |
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Answer» Solution :Current DENSITY, `J = I/A = (2)/( 10 ^(-6)) = 2 xx 10 ^(6) A //m ^(2)` `J = n E V _(d)` `or V _(d) = (J )/( n e) = ( 2 xx 10^(6))/( 8 xx 10 ^(28) xx 1. 6 xx 10 ^(-19))` `= 15.6 xx 10 ^(-5) ms ^(-1)` |
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