1.

A copper wire of length 3m and diameter 1 mm is stretched to increase it's length by0.3 cm. What is the lateral contraction produced in the wire ?poison ratio is 0.25.

Answer»

Solution :`(DELTA D)/D = delta (delta L)/L = (0.25 xx 0.3 xx 10^-2)/3` = `025 xx 10^-3` there for `delta D = 25 xx 10^-5 xx 1 xx 10^-3 = 2.5 xx 10^-7`


Discussion

No Comment Found

Related InterviewSolutions