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A copper wire of length l metre is bent to form a circular loop. If I amp current flows through the loop, find out the magnitude of magnetic moment of the loop. Or, Write down the Biot-Savart law. Show its vector form. |
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Answer» <P> Solution :CIRCUMFERENCE `= 2PI r = l or, r = (l)/(2pi)m`So, area of the LOOP, A = `pi r^(2) = pi((l)/(2pi))^(2) = (l^(2))/(4pi)m^(2)` ` therefore` Magnitude of magnetic moment, `P_(m) = IA = (il^(2))/(4pi) Acdot m^(2)` |
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