1.

A cork suspended from the bottom of a container filled with water with a string as shown in figure. If the container accelerate in a horizontal direction towards right. Which one is correct ?

Answer»

Inclination of string with vertical is `TAN^(-1)(a//g)` towards left
Inclination of string with vertical is `tan^(-1)(a//g)` towards right
Inclination of string with vertical is `pi//2-tan^(-1)(a//g)` towards left.
Inclination of string with vertical is `pi//2-tan^(-1)(a//g)` towards right.

Solution :`mgL sin THETA=ma L cos theta`
`rArr tantheta=(a)/(g)`
`theta=tan^(-1)((a)/(g))`


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