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A(cosC-cosB) = 2(b-c)cosplease prove it with full detail...Jai Hind..brainliest for proper one and like + follow to answered one |
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Answer» Step-by-step explanation: a = K sinA, B = k SINB, c = k sinC RHS b-c/a cos A/2 = (ksinB - ksinC/k sinA )cos A/2 = {[2 cos B+C/2 Sin B-C/2]/ Sin A} cos A/2 =[2* Sin B-C/2 cos (pi/2-A/2) .cos A/2] / sinA = [SinA* sinB-C/2] / sinA = Sin B-C/2 = LHS |
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