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A(cosC-cosB) = 2(b-c)cosplease prove it with full detail...Jai Hind..brainliest for proper one and like + follow to answered one ​

Answer»

Step-by-step explanation:

a = K sinA, B = k SINB, c = k sinC

RHS

b-c/a cos A/2

= (ksinB - ksinC/k sinA )cos A/2

= {[2 cos B+C/2 Sin B-C/2]/ Sin A} cos A/2

=[2* Sin B-C/2 cos (pi/2-A/2) .cos A/2] / sinA

= [SinA* sinB-C/2] / sinA

= Sin B-C/2

= LHS



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