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A crane can lift up `10,000 kg` of coal in `1` hour form a mine of `180 m` depth. If the efficiency of the crane is `80 %`, its input power must be `(g = 10 ms^(-2))`.A. 5 kWB. 6.25 kWC. 50 kWD. 62.5 kW |
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Answer» Correct Answer - B `eta = (P_("out"))/(P_("in"))`, where `P_("out") = (W)/(t) = (mgh)/(t)`. |
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