1.

A cricket ball of mass 0-5 kg strikes a bat normally with a velocity of 30 ms^(-1) and rebounds with a velocity of 20 ms^(-1) in the opposite direction. The impulse of the force exerted by the ball on the bat is :

Answer»

`0.5 Ns`
25 Ns
50 NS
1.0 Ns

Solution :I = [Change in MOMENTUM] = `mv - (- m upsilon’)`
`= m(upsilon +upsilon’) = 0.5 (30 + 20) = 25 Ns`
HENCE CORRECT choice is (b)


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