InterviewSolution
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InterviewSolution
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A cricketer can throw a ball to a maximum horizontal distance of 100m. How much high above the ground can the cricketer throw the same ball? |
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Answer» SOLUTION :`R_max=100m=v^2/G`As` v^2-u^2=2as` Here `v=0, a=-g s=R_max=100m` `THEREFORE(0^2)-u^2=2(-g)s or S=1/2u^2/g` SINCE u=v, S=1/2 v^2/g = 1/2xx100m=50m` |
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