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| 1. |
A crystal diode having internal resistance r_f =20Omega is used for half-wave rectification. if the applied voltage v = 50 sin omegat and load resistance R_L = 800Omega find: d.c. output voltage |
| Answer» SOLUTION :v=50 SIN `OMEGAT`therefore` MAXIMUM voltage, `V_m=5V` d.c. OUTPUT voltage `I_(dc)R_L=19.4mAxx800Omega=15.52"volts"` | |