1.

A cube is made from six thin insulating square faces, each square having side 'd' and carrying a uniformly distributed charge of Q. The magnitude of electric flux leaving the sixth face, due to the electric field of other five faces, is varphi. The magnitude of electrostatic force on each face of cube is F. Then,

Answer»

`varphi = (5Q)/(6E_0)`
`varphi = (Q)/(2E_0)`
`F = (2Q^(2))/(E_(0)d^(2))`
`F = (Q^(2))/(E_(0)d^(2))`

Solution :Self leaving FLUX on each FACE `= varphi`
`varphi + varphi' = Q/E_(0) IMPLIES phi = varphi' = Q/(2E_(0))`
`F = sigma INT EdA COS theta = sigma Q/(2E_(0)) = (Q^2)/(2 E_(0)d^(2))`.


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