Saved Bookmarks
| 1. |
A cube of side b has a charge g at each of its vertices. Determine the potential and electric field due to this charge array at the centre of the cube. |
|
Answer» SOLUTION :Consider a cube ABCDEFGH of side b each and let a charge q beplaced at all the 8 vertices of the cube. We KNOW that distance of centre point o of the cube from any vertex `r = (b sqrt3)/2`. `:.` Total potential at point O `V = 8 XX 1/(4pi epsi_0). q/r = 8/(4pi epsi_0) .q/((bsqrt3)/2) = (4Q)/(sqrt3pi epsi_0b)` The resultant electric field at point O is zero because electric field is a vector and the fields due to diagonally opposite charges of cube, being equal but opposite, nullify each other. |
|