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A cube of wood of volume of 0.2m3 and density 600kg/m3 is placed in a liquid of density 800kg/m3 . What fraction of the volume of the wood be immersed in the liquid |
Answer» Answer:Given:
Volume of WOOD = 0.2 m3 Density of wood = 600 kg/m3 Density of liquid = 800 kg/m3 Solution:Let the fraction of volume of wood inside liquid be ‘V’. WEIGHT of liquid displaced = weight of the wood => (800)(v)(g) = (600)(0.2)(g) => v = 120/800 = 0.15 m3 Thus, fraction of the volume of wood inside liquid is = 0.15/2 = 0.075 |
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