Saved Bookmarks
| 1. |
A cubical vessel of side 1 m contains one mole of nitrogen at a temperature of 300 K. If the molecuels are assuming to move with the rms velocity further if the vessel now thermally insulated moved with a constant speed v and then suddenly stopped and this results in rise of temperature by 2^(@)C, find v. |
|
Answer» SOLUTION :When container is moving at speed v, the kinetic energy in the nitrogen molecules is `E_(k)=(1)/(2)Mv^(2)` `=(1)/(2)xx28xx10^(-3)xxv^(2)` [Mass of 1 mole of gas `=28xx10^(-3)kg`] When the container is suddenly stopped, this kinetic energy is TRANSFORMED into thermal energy and increases the internal energy of gas as container is insulated. If temperature increment of gas is `DELTAT`, rise in its internal energy is `DeltaU=(F)/(2)nR DeltaT` `DeltaU=(5)/(2)nR DeltaT` `=(5)/(2)xx1xx8.314xx2` `=41.57` joule From energy conservation, we have `(1)/(2)xx28xx10^(-3)XX v^(2)=41.57` or `""v=sqrt((41.57xx2)/(28xx10^(-3)))` `=54.5" m"//"s"` |
|