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A cup contains 250 g of water. Find the total positive charge present in the cup of water.A. `1.34xx10^(19) C`B. `1.34xx10^(7) C`C. `2.43xx10^(19) C`D. `2.43xx10^(7) C` |
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Answer» Correct Answer - B Mass of water = 250 g, Molecular mass of water = 18 g Number of molecules in 18 g of water = `6.02xx10^(23)` Number of molecules in one cup of water `=250/18xx6.02xx10^(23)` Each molecule of water contains two hydrogen atoms and one oxygen atom, i.e., 10 electrons and 10 protons. `therefore" "` Total positive charge present in one cup of water `=250/8xx6.02xx10^(23)xx10xx1.6xx10^(-19)C=1.34xx10^(7)C` |
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