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A cup of tea cools from 65.5^@C" to " 62.5^@C in 1minute in a room at 22.5^@CHow long will it take to cool from 46.5^@C " to " 40.5^@CC in the same

Answer»

4 minutes
2 minutes
1 minutes
3 minutes

Solution :`(DT)/(dt)=k(theta-theta_(o))`
(I) `3/1=k(64-22.5)`
`3/1=k(41.5)""...(1)`
(II) `6/t=k(43.5-22.5)`
`6/t=k(21)" "...(2)`
`((1))/((2))rArr3/1xxt/6=41.5/21`
t = 4 MIN


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