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A current -carrying circular loop lies on a smooth horizonatal plane. Can a unifrom magnetic field be set up in such a manner that the loop turns around itself (i.e, turns about the vertical axis ) ? b. A current -carrying circular loop is located in a uniform external magnetic field. If the loop is free to turn , what is its orientation of stable equilibrium ? Show that in this orientation , the flux of the total field (external field + field produced by the loop ) is maximum . c.A loop irregular shape carrying current is located in an external magnetic field. If the wire is flexible, why does it chage to a cirucalr shape ? |
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Answer» Solution :No, because that WOULD require `tau` to be in LOCATED in the vertical direction . But `tau = I A xx B` and since A of the horizontal loop is in the vertical direction, `tau` would be in the plane of the loop for any B. b. Orientation of stable equilibrium is one where the area vetor A of the loop is ini the direction of external magnetic field.the magnetic field PRODUCED by the loop is in the same direction as external field . both normal to the plane of the loop , thus giving rise to maximum flux of the total field. C. It assumes circular shape with its plane normal to the field to maximize flux, since for a given PERIMETER, a circle encloses greater are than any other shape . |
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