1.

A current carrying circular loop of radius R is placed in the x-y plane with centre at the origin. Half of the loop with xgt0 is now bent so that it now lies in the y-z plane.

Answer»

The magnitude of magnetic moment now diminishes.
The magnetic moment does not change.
The magnitude of B at `(0,0,z),zgtgtR` INCREASES.
The magnitude of B at `(0,0,z),zgtgtR` is unchanged.

Solution :As the direction of magnetic field due to current carrying circular loop is PERPENDICULAR and it is perpendicular to plane of loop and unidirectional. Magnetic moment (magnitude),
`M=IA=I(pir^(2))`

When ring is bent, dipole moment for each part,
`M.-Ipi(r/2)^(2)" "[becausem=IA]`
`M.=(IPIR^(2))/4`
Resultant magnetic moment for both circular ring,
`M_("net")=sqrt((M.)^(2)+(M.)^(2))=sqrt2M.=sqrt2(Ipir^(2))/4`
Thus, `M_("net")ltM`
Thus, resultant moment will DECREASE.


Discussion

No Comment Found

Related InterviewSolutions