1.

A current carrying coil (I = 5A, R = 10 cm.) having 50 number of turns find field at its centre-A. 1.57 mTB. 3.14 mTC. 1 mTD. 2 mT

Answer» Correct Answer - A
Magnetic field at the centre of coil `B = (mu_(0)iN)/(2a)`
`(4pixx10^(-7)xx5xx50)/(2xx10//100)=1.57xx10^(-3)T`
=1.57mT.


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