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A current-carrying coil with magnetic moment \(\vec M\) (M = 5 A∙m2) is placed in a uniform magnetic field of induction \(\vec B\) (B = 0.2 Wb/m2) such that the angle between \(\vec M\) and \(\vec B\) is 30°. What is the torque acting on the coil ? |
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Answer» τ = MB sin θ = (5) (0.2) sin 30° = 0.5 N∙m is the torque acting on the coil. |
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