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A current flowing through a coil changes from +2A to -2A in 0.05 s and an emf of 8 V is induced in the coil. The value of self-inductance of the coil isA. 0.8 HB. 0.1 HC. 0.2 HD. 0.4 H |
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Answer» Correct Answer - B We know, `e=-L(dI)/(dt)` or, `L=(-edt)/(dI)=(8xx0.05)/(-2-(+2))=(0.4)/(4)=0.1H` |
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