InterviewSolution
Saved Bookmarks
| 1. |
A semicircular wire of radius r is rotating with angular velocity `omega` in a uniform magnetic field B with its radius as axis. If the resistance of the circuit be R and if the axis of rotation remains perpendicular to B, what will be the average power produced in each period? |
|
Answer» Magnetic flux, `phi=BAcosomegat=B.(pir^(2))/(2).cosomegat` `therefore` emf induced, `e=-(dphi)/(dt)=(Bpir^(2))/(2)omegasinomegat` Power, `P=(e^(2))/(R)=((Bpir^(2)omega)^(2))/(4R)sin^(2)omegat` In a complete period, the average of `sin^(2)omegat=(1)/(2)` So, the average power, `barP=((Bpir^(2)omega)^(2))/(8R)` |
|