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A current I flows around a closedpath in the horizontal plane of the circle as shown in the figure. The path consists of eight arcs with alternating radii r and 2r. Each segment of arc subtends equal angle at the common centre P. Find the magnetic field produced by current path at point P |
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Answer» Solution :B due to STRAIGHT parts of the WIRE is zero. Each arc SUBTENDS an angle `theta = (2PI)/(8) = pi //4` `therefore B_("net") = 4 ((mu_0 I)/(4pi r) xx pi//4) + 4 ((mu_0 I)/(4pi (2r)) xx pi // 4 )` ` = (3 mu_0 I)/(8r)`, perpendicular to the plane fo the paper and DIRECTED inward. |
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