1.

A current I flows through a long straight conductor which is bent into a circular loop of radius R in the middle as shown in the figure . The magnitude of the net magnetic field at point O will be

Answer»

Zero
`(mu_0I)/(2R)(1+pi)`
`(mu_0I)/(4piR)`
`(mu_0I)/(2R)(1-1/pi)`

Solution :[Hint: Field at O due to long STRAIGHT conductor , `B_(1)=(mu_0I)/(2piR)o.` and field at O due to circular LOOP `B_(2)=(mu_0I)/(2R)ox . :.` Net magnetic field at O,`B=B_(2)-B_(1)=(mu_0I)/(2R)(1-1/pi)ox` ]


Discussion

No Comment Found

Related InterviewSolutions