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A current is made of two components a dc component i_(1)=3A and an ac component i_(2)=4sqrt2 sin omegat. Find the reading of hot wire ammeter. |
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Answer» Solution :`i=i_(1)+i_(2)=3+4sqrt2 sin OMEGAT` `i_("RMS")^(2)=(int_(0)^(T)i^(2).dt)/(int_(0)^(T)dt)=(int_(0)^(T)(3+4sqrt2sin omega t)^(2)dt)/(T)` `i_("rms")^(2)=(1)/(T)int_(0)^(T)(9+24sqrt2sin omega t+32 sin^(2)omegat)dt` `THEREFORE i_("rms")=5A` |
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