1.

A current is passed through two cells connected in series. The first cell contain x(NO_(3))_(2) (aq) and the second cell contains y(NO_(3))_(2)(aq) . The relative atomic masses of x and y are in the ratio of x to that of y?

Answer»

`3:2`
` 1:2`
`1:3`
` 3:1`

Solution :If atomic mass of x=a, then that of y=2a
`therefore` Eq. mass `=("at. Mass")/("VALENCY")`
`therefore` Eq. mass of `x=a//3`. Eq mass of
`y=2a//2=a`.
`("Mass of x")/("Mass of y")=("Eq. mass of x")/("E Q mass of y")`
`=(a//3)/(1)=(1)/(3)= 1:3`


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