1.

A current is passed through two cells connected in series. The first cell contains X(NO_(3))_(3(aq)) and the second cell contains Y(NO_(3))_(2(aq)). The relative atomic masses of X and Y are in the ratio 1:2. What is the ratio of liberated mass of X to that of Y.

Answer»

`3:2`
`1:2`
`1:3`
`3:1`

SOLUTION :The oxidation STATES of X and Y are `X^(3+) and Y^(2+)` given atomic masses are in the ratio of 1:2
`therefore` Equivalent masses are in the ratio
`(1)/(3):(2)/(2)` or `(1)/(3):1` or `1:3`


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