1.

A current is passed through two cells connected in series. The first cell contians X(NO_(2))_(2)(aq). The relative atomic masses of X and Y are in the ratio 1:2. What is the ratio of the liberated mass of X to that of Y ?

Answer»

`3:2`
`1:2`
`1:2`
`3:3`

Solution :(c ) The OXIDATION STATES of X and Y in their respective nitrates are 3 and 2 RESPECTIVELY. The equivalent masses of the METALS can be calculated by dividing the respective atomic masses with oxidation states or valences. These are in the ratio `1//3 : 2//2` or `1//3 : 1` or `1:3`


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