1.

A current is passed through two cells connected in series. The first cell contains X(NO_(3))_(3)(aq) and the second cell contains Y(NO_(3))_(2)(aq). The relative atomic masses of X and Y are in the ratio 1:2, what is the ratio of the liberated mass of X to that of Y?

Answer»

`3:2`
`1:2`
`1:3`
`3:1`

SOLUTION :if atomic MASS of X=a, then that of Y=2a. As eq.WT=atomic mass/valency,
Eq. wt. of X=a/3, Eq. wt. of Y=2 a/2=a.
`("Mass of "X)/("Mass of "Y)=("Eq. wt. of "X)/("Eq. wt. of Y")=(a//3)/(a)=(1)/(3)=1:3`


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