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A current loop is considered a magnetic dipole. Explain. Also give an expression for its dipole moment. |
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Answer» Solution :CONSIDER a plane loop of wire carrying current I as shown in Fig. Looking at the upper face, current is anticlockwise and , therefore , it has a north polarity. Looking at the lower face of the loop, the current is clockwise and hence it has a south polarity. The current loop, THUS, behaves as a magnetic dipole. The magnetic MOMENT `vecm` of a current loop is equal to the product of current I and area A enclosed by the loop. Thus, `vecm = I vecA` If instead of a single loop, we have a coil of N TURNS, then its magnetic moment. `vec(m) = N I vecA` 
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