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A current of `0.1 A` circulates around a coil of 100 turns and having a radius equal to `5 cm`. The magnetic field set up at the centre of the coil is (`mu_(0)=4pixx10^(-7)` weber/amper-metre)A. `4pi xx1-^-5`teslaB. `8pixx10^-7` teslaC. `4xx10^-5` teslaD. `2xx10^-5` tesla |
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Answer» Correct Answer - A `B=(mu_0nI)/(2a)=(4pixx10^-7xx100xx0.1)/(1xx5xx10^-2)=4pixx10^(-5)T` |
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