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A current of `0.1 A` circulates around a coil of 100 turns and having a radius equal to `5 cm`. The magnetic field set up at the centre of the coil is (`mu_(0)=4pixx10^(-7)` weber/amper-metre)A. `5pixx10^(-5)T`B. `8pixx10^(-5)T`C. `4pixx10^(-5)T`D. `4pixx10^(-5)T` |
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Answer» Correct Answer - C Magnetic field at the centre of circular coil of N turns is given by `B=(mu_(0)Ni)/(2r)=(4xx10^(-7)xx100xx0.1)/(2xx5xx10^(-2))=4pxx10^(-6)T` |
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