1.

A current of 0.1A was passed for 4hr through a solution of cuprocyanide and 0.3745 g of copper was deposited on the cathode. Calculate the current efficiency for the copper deposition. (Cu GAM 63.5 or Cu-63.5)

Answer»

`79%`
`39.5%`
`63.25%`
`63.5%`

SOLUTION :`m("THEORETICAL")=(63.5xx0.1xx7200)/96500=0.4738` G
`therefore % "EFFICIENCY" =0.3745/0.4738xx100=79%`


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